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Reduccion Inversa

 
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1x2quiniela
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Joined: 05 Sep 2007
Posts: 52
Location: Estados Unidos

PostPosted: Tue Sep 30, 2008 3:13 pm    Post subject: Reduccion Inversa Reply with quote

Hola,

Una reducida tiene la forma C(v, k, t, m, l)=b


La inversa de una reducida seria C(v, v-k, (v-m)-(k-t), v-m, l)=b


Por lo que al crear una reducida record tambien se crea record a la inversa..


Ejemplo:

La reducida C(14,6,4,5)=29
La inversa seria C(14,8,7,9)=29



Voy a poner un ejemplo de Reduccion Inversa,

La reducida perfecta de quiniela 15D-R13 2048 esta formada por las siguientes reducciones de loto:

15D-R13 K=0 1
15D-R13 K=1 0
15D-R13 K=2 0
15D-R13 K=3 35
15D-R13 K=4 105
15D-R13 K=5 168
15D-R13 K=6 280
15D-R13 K=7 435
15D-R13 K=8 435
15D-R13 K=9 280
15D-R13 K=10 168
15D-R13 K=11 105
15D-R13 K=12 35
15D-R13 K=13 0
15D-R13 K=14 0
15D-R13 K=15 1

Escogemos la siguente 15D-R13 K=3 35

C( 15 3 2 2 )= 35

1 2 12
1 3 13
1 4 14
1 5 15
6 14 15
2 6 13
3 6 12
4 5 6
7 13 15
2 7 14
4 7 12
3 5 7
8 13 14
2 8 15
3 4 8
5 8 12
6 7 8
9 12 15
3 9 14
4 9 13
2 5 9
1 8 9
10 12 14
3 10 15
2 4 10
5 10 13
1 7 10
6 9 10
11 12 13
2 3 11
4 11 15
5 11 14
1 6 11
7 9 11
8 10 11

y buscamos en la formula C(v, v-k, (v-m)-(k-t), v-m, l)=b la inversa:



V K T M B L
15 3 2 2 35 1 C( 15 3 2 2 )= 35


V K T M B L
15 12 12 13 35 1 C( 15 12 12 13 )= 35


Entonces la inversa es 15D-R13 K=12 35

C( 15 12 12 13 )= 35

1 2 3 4 5 6 7 9 12 13 14 15
1 2 3 4 5 6 8 10 12 13 14 15
2 3 4 5 7 8 9 10 12 13 14 15
1 2 3 4 6 7 8 9 10 12 13 15
1 2 3 5 6 7 8 9 10 12 13 14
1 4 5 6 7 8 9 10 12 13 14 15
1 2 3 4 5 6 7 8 9 10 14 15
1 2 3 4 5 7 8 11 12 13 14 15
2 3 4 5 6 8 9 11 12 13 14 15
1 2 3 4 6 7 8 9 11 12 14 15
1 3 5 6 7 8 9 11 12 13 14 15
1 2 4 5 6 7 8 9 11 12 13 14
1 2 3 4 5 6 7 8 9 11 13 15
2 3 4 5 6 7 10 11 12 13 14 15
1 3 4 6 7 8 10 11 12 13 14 15
1 2 3 5 6 7 8 10 11 12 14 15
1 2 4 5 6 7 8 10 11 12 13 15
1 2 3 4 5 6 7 8 10 11 13 14
1 2 3 4 5 9 10 11 12 13 14 15
1 2 3 4 6 7 9 10 11 13 14 15
1 2 5 6 7 9 10 11 12 13 14 15
1 3 4 5 6 7 9 10 11 12 13 14
1 2 3 4 5 6 7 9 10 11 12 15
1 2 4 6 8 9 10 11 12 13 14 15
1 2 3 5 6 8 9 10 11 13 14 15
1 3 4 5 6 8 9 10 11 12 13 15
1 2 3 4 5 6 8 9 10 11 12 14
1 2 3 7 8 9 10 11 12 13 14 15
1 2 4 5 7 8 9 10 11 13 14 15
1 3 4 5 7 8 9 10 11 12 14 15
1 2 3 4 5 7 8 9 10 11 12 13
2 3 4 6 7 8 9 10 11 12 13 14
2 3 5 6 7 8 9 10 11 12 13 15
2 4 5 6 7 8 9 10 11 12 14 15
3 4 5 6 7 8 9 10 11 13 14 15

La reducida15D-R13 2048 esta formada por 1024 columnas:

15D-R13 K=0 1
15D-R13 K=1 0
15D-R13 K=2 0
15D-R13 K=3 35
15D-R13 K=4 105
15D-R13 K=5 168
15D-R13 K=6 280
15D-R13 K=7 435

Y las otras 1024 columnas son la inversa de las primeras o viceversa:

15D-R13 K=8 435
15D-R13 K=9 280
15D-R13 K=10 168
15D-R13 K=11 105
15D-R13 K=12 35
15D-R13 K=13 0
15D-R13 K=14 0
15D-R13 K=15 1


Conclusion: La reducida inversa es muy facil de hacer, solo hay que completar la serie hasta llegar a v, en este caso v=15..

Ejemplo:
1 2 3 4 5 6 7 9 12 13 14 15------------Faltaria Inversa 8 10 11


Saludos
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